Optimal. Leaf size=60 \[ -\frac{3}{4 d \left (a^2 \cos (c+d x)+a^2\right )}-\frac{\tanh ^{-1}(\cos (c+d x))}{4 a^2 d}+\frac{1}{4 d (a \cos (c+d x)+a)^2} \]
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Rubi [A] time = 0.126629, antiderivative size = 60, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.263, Rules used = {3872, 2836, 12, 88, 206} \[ -\frac{3}{4 d \left (a^2 \cos (c+d x)+a^2\right )}-\frac{\tanh ^{-1}(\cos (c+d x))}{4 a^2 d}+\frac{1}{4 d (a \cos (c+d x)+a)^2} \]
Antiderivative was successfully verified.
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Rule 3872
Rule 2836
Rule 12
Rule 88
Rule 206
Rubi steps
\begin{align*} \int \frac{\csc (c+d x)}{(a+a \sec (c+d x))^2} \, dx &=\int \frac{\cos (c+d x) \cot (c+d x)}{(-a-a \cos (c+d x))^2} \, dx\\ &=\frac{a \operatorname{Subst}\left (\int \frac{x^2}{a^2 (-a-x) (-a+x)^3} \, dx,x,-a \cos (c+d x)\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \frac{x^2}{(-a-x) (-a+x)^3} \, dx,x,-a \cos (c+d x)\right )}{a d}\\ &=\frac{\operatorname{Subst}\left (\int \left (\frac{a}{2 (a-x)^3}-\frac{3}{4 (a-x)^2}+\frac{1}{4 \left (a^2-x^2\right )}\right ) \, dx,x,-a \cos (c+d x)\right )}{a d}\\ &=\frac{1}{4 d (a+a \cos (c+d x))^2}-\frac{3}{4 d \left (a^2+a^2 \cos (c+d x)\right )}+\frac{\operatorname{Subst}\left (\int \frac{1}{a^2-x^2} \, dx,x,-a \cos (c+d x)\right )}{4 a d}\\ &=-\frac{\tanh ^{-1}(\cos (c+d x))}{4 a^2 d}+\frac{1}{4 d (a+a \cos (c+d x))^2}-\frac{3}{4 d \left (a^2+a^2 \cos (c+d x)\right )}\\ \end{align*}
Mathematica [A] time = 0.174836, size = 83, normalized size = 1.38 \[ -\frac{\sec ^2(c+d x) \left (6 \cos ^2\left (\frac{1}{2} (c+d x)\right )+4 \cos ^4\left (\frac{1}{2} (c+d x)\right ) \left (\log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )-\log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )\right )-1\right )}{4 a^2 d (\sec (c+d x)+1)^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.06, size = 72, normalized size = 1.2 \begin{align*}{\frac{1}{4\,d{a}^{2} \left ( \cos \left ( dx+c \right ) +1 \right ) ^{2}}}-{\frac{3}{4\,d{a}^{2} \left ( \cos \left ( dx+c \right ) +1 \right ) }}-{\frac{\ln \left ( \cos \left ( dx+c \right ) +1 \right ) }{8\,d{a}^{2}}}+{\frac{\ln \left ( -1+\cos \left ( dx+c \right ) \right ) }{8\,d{a}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.00546, size = 100, normalized size = 1.67 \begin{align*} -\frac{\frac{2 \,{\left (3 \, \cos \left (d x + c\right ) + 2\right )}}{a^{2} \cos \left (d x + c\right )^{2} + 2 \, a^{2} \cos \left (d x + c\right ) + a^{2}} + \frac{\log \left (\cos \left (d x + c\right ) + 1\right )}{a^{2}} - \frac{\log \left (\cos \left (d x + c\right ) - 1\right )}{a^{2}}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.70344, size = 294, normalized size = 4.9 \begin{align*} -\frac{{\left (\cos \left (d x + c\right )^{2} + 2 \, \cos \left (d x + c\right ) + 1\right )} \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) -{\left (\cos \left (d x + c\right )^{2} + 2 \, \cos \left (d x + c\right ) + 1\right )} \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) + 6 \, \cos \left (d x + c\right ) + 4}{8 \,{\left (a^{2} d \cos \left (d x + c\right )^{2} + 2 \, a^{2} d \cos \left (d x + c\right ) + a^{2} d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\csc{\left (c + d x \right )}}{\sec ^{2}{\left (c + d x \right )} + 2 \sec{\left (c + d x \right )} + 1}\, dx}{a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.30401, size = 117, normalized size = 1.95 \begin{align*} \frac{\frac{2 \, \log \left (\frac{{\left | -\cos \left (d x + c\right ) + 1 \right |}}{{\left | \cos \left (d x + c\right ) + 1 \right |}}\right )}{a^{2}} + \frac{\frac{4 \, a^{2}{\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} + \frac{a^{2}{\left (\cos \left (d x + c\right ) - 1\right )}^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}}{a^{4}}}{16 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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